(answered) – 1) For the following reaction,3.87 grams of carbon (graphite)areDescriptionSolution downloadThe Question1) For the following reaction,3.87?grams of?carbon (graphite)are allowed to react with?14.0?grams of?oxygen gas.carbon (graphite)(s) +oxygen(g)carbon dioxide(g)What is the maximum amount of?carbon dioxide?that can be formed?gramsWhat is the?FORMULA?for the limiting reagent?2)For the following reaction,26.7grams ofsulfur dioxideare allowed to react with5.46grams ofoxygen gas.sulfur dioxide(g) +oxygen(g)sulfur trioxide(g)What is the maximum amount ofsulfur trioxidethat can be formed??____gramsWhat is the?FORMULA?for the limiting reagent?What amount of the excess reagent remains after the reaction is complete?____grams3)It is often possible to change a hydrate into an anhydrous compound by heating it to drive off the water (dehydration).A?49.14?gram sample of a hydrate of?MnSO4?was heated thoroughly in a porcelain crucible, until its weight remained constant. After heating,?43.90?grams of the anhydrous compound remained. What is the formula of the hydrate?Use a period instead of a dot in the formula of the hydrate.4) A student is running an experiment in which?49.3?grams of?CaSeO4?is needed, but the only jar of reagent in the lab is labelled?calcium selenate dihydrate. How many grams of the hydrate must the student weigh out in order to get the desired amount of the anhydrous compound??_____g?CaSeO42H2O
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