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(answered) – 1) A patient is to be injected with 0.5L of an electrolyte

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(answered) – 1) A patient is to be injected with 0.5L of an electrolyteDescriptionSolution downloadThe Question1) A patient is to be injected with 0.5L of an electrolyte solution in 1/2 hour. Assuming that the solution is elevated by 1m above the arm, and that hydrostatic pressure alone is used to push the solution into the arm (as is typical of an IV), and assuming that the needle itself is 2.5cm long, what inner diameter must the needle have to allow this? (use???= 1×10^-3 Ns/m2, and??=1000kg/m3; the values for water) Also assume that the pressure in the patients vein is atmospheric pressure.?2)?Cherry-pit spitting competitions are stupid. Nonetheless, “boys will be boys”. If a typical cherry pit is spherical, with 4mm diameter, what’s the fastest speed it can be spat out before it is expected to set up turbulent air flows around it, thereby making its trajectory less efficient? The viscosity of air with density is 1.1kg/m3 is 0.00002 N-s/m2. (b) If a much smaller pit is found, one with half the diameter of the first, how much faster can IT now be spat before turbulent flow is expected? (Note: In this question the turbulent flow is only for initial conditions, as the airs viscosity will quickly slow down the pit mid-air, thus reducing the Reynolds number to below streamline levels. So, turbulent flow may only be expected during the early stages of the trajectory).?3) A horizontal tube with a constriction and two open, vertical columns. Ignore the viscosity of water. The inner radius of the larger section of the horizontal tube is 1.25cm. Water passes through the tube at a rate of 0.18 L/s. If h1=10cm and h2=5cm, what is the inner radius at the constriction? (This is a toughie! Use various concepts of continuity, Bernoulli’s law and hydrostatic pressure to figure out what is going on.)?-Attached is a file for the formula Sheet. The answer for question one is Diameter=0.44mm. The answer for question two a is: keep speed below 9m/s (32km/h) for streamline flow. B) V2=2V1; allowing a greater initial speed of 18m/s. The answer for question 3 is 7.5mm wide. But I need to know the process and the formulas to use to get to these answers.?Trent University: PHYS-BIOL 1060HFormula Sheet?x= tan ?lstress ? shearG?=strain ? shearShear Strain:? shear ?1. GeneralWeight:Fg ? W = mg (SI units: newtons, N)GM 1 M 2r2Newton?s 2nd Law: F = ma (SI: N)2Kinetic Energy: E = 1 / 2mv (SI: joules, J)1 22Circle: Area= ?r = ?D4perimeter= 2?r = ?D2cylinder: Area= 2?rl + (2 ? ?r ) (shaft + bases)2volume= ?r lRectangle:Area= L ? Wperimeter= 2( L + W )22Sphere: Surface Area= 4?r = ?D4?r 3Volume=332Cube: Surface Area= 6L Volume= LGravitational Law:F=?2/3-law? surface area to mass relationship:A ? M 2/3?1/4-law? surface area to mass relationship:A? M5/8massmDensity: ? ==volume V?=F?l=Y= Y?Al0Breaking Stress:? max? shear =solid cylinder twist:Fshear?x=G= G?Al0G?r 3? twistFtngnt =2lhollow cylinder twist:Ftngnt =Elastic Energy stored in strain:22G?trave? twistlU elast ? Yl? 2 ? Y (?l ) 2122F?v=?A?yF?vfor Viscoelastic fluids:= G? shear + ?A?yliquid shear & viscosity:P1 ? P2 2(R ? r 2 )4?L?R 4 ?PFlow Rate: Q = Av ave =8?L?v ave DReynold?s number of flow: Re =Flow profile in a tube:v=?Stoke?s law for drag at high viscosity (for sphere):Fd = 6? ? r v2. FluidsPressure:FP?AGauge Pressure:Pgauge = Pabs ? PatmHydrostatic pressure:Pabs = Patm + ?ghTerminal speed of spherical sinking/floating objects:F= ? fluidVdisplaced gbuoyancyForce Surface EnergySurface Tension: ?

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